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|The problem is that widescreen needs to have the lower number evenly divisible by both 9 and 8. There are only a few like that. 9X8=72 so use that as a starting point. On the small side, 72X3=216. That would be 384X216 using square pixels. (Width is height divided by 9 times 16) |} * ...and much more!

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  • FAQ:Why are there black borders/bars?
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  • |The problem is that widescreen needs to have the lower number evenly divisible by both 9 and 8. There are only a few like that. 9X8=72 so use that as a starting point. On the small side, 72X3=216. That would be 384X216 using square pixels. (Width is height divided by 9 times 16) |} * ...and much more!
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  • |The problem is that widescreen needs to have the lower number evenly divisible by both 9 and 8. There are only a few like that. 9X8=72 so use that as a starting point. On the small side, 72X3=216. That would be 384X216 using square pixels. (Width is height divided by 9 times 16) |} * ...and much more!
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