OpenLink Software

Usage stats on Adding Consecutive Numbers

 Permalink

an Entity in Data Space: 134.155.108.49:8890

The count is easy and try but there is a faster shortcut. You can count 1+2+3+4+5+6+... tiring right. There a shortcut for it is to take as 1+2+3+4+...+n First take n/2 next take n+1 then mutiply (n/2)(n+1) is 1+2+3+...+n n is an algebrabic unit. try 10 10/2=5 10+1=11 5*11=55 or take 1+2+...+n-1+n = take half of n then add half then take yor number after that multipy (n/2+1/2)n if x = sum (1...n) then x + (n + 1) = n * (n+1) / 2 + (n + 1) x + (n + 1) = (n * (n + 1) + 2n +2) / 2 x + (n + 1) = ((n*n + n) + 2n + 2) / 2 x + (n + 1) = (n*n + 3 *n + 2) / 2 x + (n + 1) = ((n + 1) * (n + 2)) / 2 Like 15+16+17+... =3030

EntityAttributeValueRank
Alternative Linked Data Views: ODE     Raw Data in: CXML | CSV | RDF ( N-Triples N3/Turtle JSON XML ) | OData ( Atom JSON ) | Microdata ( JSON HTML) | JSON-LD    About   
This material is Open Knowledge   W3C Semantic Web Technology [RDF Data] This material is Open Knowledge Creative Commons License Valid XHTML + RDFa
This work is licensed under a Creative Commons Attribution-Share Alike 3.0 Unported License.
OpenLink Virtuoso version 07.20.3217, on Linux (x86_64-pc-linux-gnu), Standard Edition
Copyright © 2009-2012 OpenLink Software