"FAQ:Why are there black borders/bars?"@en . . . . . . . "|The problem is that widescreen needs to have the lower number evenly divisible by both 9 and 8. There are only a few like that. 9X8=72 so use that as a starting point. On the small side, 72X3=216. That would be 384X216 using square pixels. (Width is height divided by 9 times 16) |} \n* ...and much more!"@en . "|The problem is that widescreen needs to have the lower number evenly divisible by both 9 and 8. There are only a few like that. 9X8=72 so use that as a starting point. On the small side, 72X3=216. That would be 384X216 using square pixels. (Width is height divided by 9 times 16) |} \n* ...and much more!"@en .